// C++ program to Find maximum XOR value in // matrix either row / column wise #include   using namespace std; // maximum number of row and column const int MAX = 1000; // function return the maximum xor value that is // either row or column wise int maxXOR(int mat[][MAX] int N) {  // for row xor and column xor  int r_xor c_xor;  int max_xor = 0;  // traverse matrix  for (int i = 0 ; i < N ; i++)  {  r_xor = 0 c_xor = 0;  for (int j = 0 ; j < N ; j++)  {  // xor row element  r_xor = r_xor^mat[i][j];  // for each column : j is act as row & i  // act as column xor column element  c_xor = c_xor^mat[j][i];  }  // update maximum between r_xor  c_xor  if (max_xor < max(r_xor c_xor))  max_xor = max(r_xor c_xor);  }  // return maximum xor value  return max_xor; } // driver Code int main() {  int N = 3;  int mat[][MAX] = {{1  5 4}  {3  7 2 }  {5  9 10}  };  cout << 'maximum XOR value : '  << maxXOR(mat N);  return 0; } 

// Java program to Find maximum XOR value in // matrix either row / column wise import java.io.*; class GFG {    // maximum number of row and column  static final int MAX = 1000;    // function return the maximum xor value   // that is either row or column wise  static int maxXOR(int mat[][] int N)  {    // for row xor and column xor  int r_xor c_xor;  int max_xor = 0;    // traverse matrix  for (int i = 0 ; i < N ; i++)  {  r_xor = 0; c_xor = 0;    for (int j = 0 ; j < N ; j++)  {    // xor row element  r_xor = r_xor^mat[i][j];    // for each column : j is act as row & i  // act as column xor column element  c_xor = c_xor^mat[j][i];  }    // update maximum between r_xor  c_xor  if (max_xor < Math.max(r_xor c_xor))  max_xor = Math.max(r_xor c_xor);  }    // return maximum xor value  return max_xor;  }    //driver code  public static void main (String[] args)  {    int N = 3;    int mat[][] = { {1 5 4}  {3 7 2}  {5 9 10}};    System.out.print('maximum XOR value : '  + maxXOR(mat N));  } } // This code is contributed by Anant Agarwal. 

 # Python3 program to Find maximum # XOR value in matrix either row / column wise # maximum number of row and column MAX = 1000 # Function return the maximum # xor value that is either row # or column wise def maxXOR(mat N): # For row xor and column xor max_xor = 0 # Traverse matrix for i in range(N): r_xor = 0 c_xor = 0 for j in range(N): # xor row element r_xor = r_xor ^ mat[i][j] # for each column : j is act as row & i # act as column xor column element c_xor = c_xor ^ mat[j][i] # update maximum between r_xor  c_xor if (max_xor < max(r_xor c_xor)): max_xor = max(r_xor c_xor) # return maximum xor value return max_xor # Driver Code N = 3 mat= [[1  5 4] [3  7 2 ] [5  9 10]] print('maximum XOR value : ' maxXOR(mat N)) # This code is contributed by Anant Agarwal. 

// C# program to Find maximum XOR value in // matrix either row / column wise using System; class GFG  {    // maximum number of row and column    // function return the maximum xor value   // that is either row or column wise  static int maxXOR(int []mat int N)  {    // for row xor and column xor  int r_xor c_xor;  int max_xor = 0;    // traverse matrix  for (int i = 0 ; i < N ; i++)  {  r_xor = 0; c_xor = 0;    for (int j = 0 ; j < N ; j++)  {    // xor row element  r_xor = r_xor^mat[i j];    // for each column : j is act as row & i  // act as column xor column element  c_xor = c_xor^mat[j i];  }    // update maximum between r_xor  c_xor  if (max_xor < Math.Max(r_xor c_xor))  max_xor = Math.Max(r_xor c_xor);  }    // return maximum xor value  return max_xor;  }    // Driver code  public static void Main ()  {    int N = 3;    int []mat = { {1 5 4}  {3 7 2}  {5 9 10}};    Console.Write('maximum XOR value : '  + maxXOR(mat N));  } } // This code is contributed by nitin mittal. 

 // PHP program to Find  // maximum XOR value in // matrix either row or  // column wise // maximum number of  // row and column $MAX = 1000; // function return the maximum  // xor value that is either // row or column wise function maxXOR($mat $N) { // for row xor and  // column xor $r_xor; $c_xor; $max_xor = 0; // traverse matrix for ($i = 0 ; $i < $N ; $i++) { $r_xor = 0; $c_xor = 0; for ($j = 0 ; $j < $N ; $j++) { // xor row element $r_xor = $r_xor^$mat[$i][$j]; // for each column : j // is act as row & i // act as column xor // column element $c_xor = $c_xor^$mat[$j][$i]; } // update maximum between // r_xor  c_xor if ($max_xor < max($r_xor $c_xor)) $max_xor = max($r_xor $c_xor); } // return maximum  // xor value return $max_xor; } // Driver Code $N = 3; $mat = array(array(1 5 4) array(3 7 2) array(5 9 10)); echo 'maximum XOR value : '  maxXOR($mat $N); // This code is contributed by anuj_67. ?> 

<script> // Javascript program to Find // maximum XOR value in // matrix either row / column wise // maximum number of row and column const MAX = 1000; // function return the maximum  // xor value that is // either row or column wise function maxXOR(mat N) {  // for row xor and column xor  let r_xor c_xor;  let max_xor = 0;  // traverse matrix  for (let i = 0 ; i < N ; i++)  {  r_xor = 0 c_xor = 0;  for (let j = 0 ; j < N ; j++)  {  // xor row element  r_xor = r_xor^mat[i][j];  // for each column : j   // is act as row & i  // act as column xor   // column element  c_xor = c_xor^mat[j][i];  }  // update maximum between r_xor  c_xor  if (max_xor < Math.max(r_xor c_xor))  max_xor = Math.max(r_xor c_xor);  }  // return maximum xor value  return max_xor; } // driver Code  let N = 3;  let mat = [[1  5 4]  [3  7 2 ]  [5  9 10]];  document.write('maximum XOR value : '  + maxXOR(mat N)); </script>